Concatenation: Difference between revisions
No edit summary |
No edit summary |
||
(One intermediate revision by the same user not shown) | |||
Line 1: | Line 1: | ||
[[String]] concatenation is the operation of joining two or more character strings end-to-end. For example, the strings "snow" and "ball" may be concatenated to give "snowball". | [[String]] '''concatenation''' is the operation of joining two or more character strings end-to-end. For example, the strings "snow" and "ball" may be concatenated to give "snowball". | ||
In BR, the operator responsible for string concatenation is the ampersand '''&'''. So, the "snowball" example above may be carried out as follows: | In BR, the operator responsible for string concatenation is the ampersand '''&'''. So, the "snowball" example above may be carried out as follows: | ||
Line 28: | Line 28: | ||
===Appending=== | ===Appending=== | ||
{{Append}} | {{:Append}} | ||
===Prepending=== | ===Prepending=== | ||
{{Prepend}} | {{:Prepend}} | ||
<noinclude> | <noinclude> |
Latest revision as of 18:37, 13 January 2014
String concatenation is the operation of joining two or more character strings end-to-end. For example, the strings "snow" and "ball" may be concatenated to give "snowball".
In BR, the operator responsible for string concatenation is the ampersand &. So, the "snowball" example above may be carried out as follows:
00010 let string1$ = "snow" 00020 let string2$ = "ball" 00030 let result$ = string1$ & string2$ 00040 print result$ ! this will print snowball
You may concatenate as many strings as you like. Note that if you are storing the concatenated result into a string variable, then this variable needs to be dimensioned long enough to fit the combined length of all the concatenated strings. Consider the following example:
00010 let string1$ = "snow" 00020 let string2$ = "ball" 00030 let string3$ = " effect of concatenating many strings" 00040 let result$ = string1$ & string2$ & string3$ ! this will result in error
The above example results in an error, because the default length of the string result$ is 18 characters, as any BR string. The combined length of string1$, string2$, and string3$ is 45 characters. Note that the error does not result from concatenating string1$ & string2$ & string3$. The error occurs when we try to assign a 45 character value to an 18 character string result$. In order to correct the error, we need to dimension result$ to at least 45 characters or more. Below is the corrected example:
00005 dim result$*45 00010 let string1$ = "snow" 00020 let string2$ = "ball" 00030 let string3$ = " effect of concatenating many strings" 00040 let result$ = string1$ & string2$ & string3$ ! this will result in error
Advanced
For increased speed of program execution, and shorter syntax you may incorporate the following methods.
Appending
To append string2$ to string1$ means to join string2$ to the end of string1$.
To append to the end of a String you should (for maximum speed of code execution) use
X$(inf:0)="append this to end"
OR
X$(inf:inf)="append this to the end"
Here, inf denotes infinity.
So X$(inf:inf) means "the substring of X$ starting at infinity". This is particularly useful when you don't know how long your string is and do not want to calculate its length.
see also: prepend
Prepending
To prepend string1$ to string2$ means to join string1$ to the beginning of string2$.
To append to the beginning of a string you should use
X$(0:0)="append this to front"
or alternately
X$(1:0)="append this to front"
For example,
00010 dim result$*255 ! dimension long enough to fit the result 00020 let result$ = " and this is the end" 00030 let string_to_prepend$ = "this is the front" 00040 let result$(0:0) = string_to_prepend$ 00050 print result$
The output of the program above will be:
this is the front and this is the end